Question

if 54g of aluminium reacts with 160g of oxygen. find out the amount of product formed?​

Answer 1

number of atom n =mass ÷molar mass

number of Al atom =54÷27=2atom of Al.

number of o atom = 160÷16=10 atom of o .

molecules of ALO2

= 3×6.022×10 (23)

18.066×10 (23)

NOW ,MASS OF ALO2

MASS OF AL MOLECULES +MASS OF O2 MOLECULES

54+160

=214U MASS of ALO2.