Question

if 56-45+
$if 56 - 45 + \sqrt{x = 17} \: thenx =$
​

Answer 1

The value of x is "36".

Step-by-step explanation:

We have,

$56 - 45 + \sqrt{x}=17$

$\sqrt{x} =17-11=6$

Squaring both sides, we get

$\sqrt{x} ^{2}=6^{2}$

⇒ x = 36

Hence, the value of x is "36".