If 56 g of CaO and 11.2 L of CO2 at STP reacted for the formation of CaCO3 as per following reaction, then which substance will be excess reagent and how much amount?
Cao+CO2 –>CaCO3
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Answer:
CaO is in excess by 0.5mole
mass of excess CaO=0.5×56=28g
Explanation:
CaO + CO2 → CaCO3
56g. 11.2L
1. 0.5
n(CaO)=56/56=1mole
n(CO2)=11.2/22.4=0.5
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