. If 56b is a multiple of 9, then what could be the possible value of b?
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Answer:
the possible value of b is 7
Step-by-step explanation:
Given number =56b
Since it is a multiple of 9 , It satisfies the divisibility by 9
"the sum of all digits in a number is divisible by 9 then given number is divisible by 9".
sum of the digits in 56b =5+6+b=11+b
we know that multiple of 9 after 11 is 18
so , 18-11=7 must be value of b
check: 567 is the number
5+6+7=18 is a multiple of 9
567 is divisible by 9
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