Question

if 56g N2 and 64g Ch4 are mixed with 80 g SO3 gas then mole fraction of Ch4 is​

Answer 1

0.57

Explanation:

Given, Mass of $N_2$ = 56 g

Molar mass of $N_2$ = 28 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{56\ g}{28\ g/mol}$

$Moles\ of\ N_2= 2\ mol$

Given, Mass of $CH_4$ = 64 g

Molar mass of $CH_4$ = 16g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{64\ g}{16\ g/mol}$

$Moles\ of\ CH_4= 4\ mol$

Given, Mass of $SO_3$ = 80 g

Molar mass of $SO_3$ = 80 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{80\ g}{80\ g/mol}$

$Moles\ of\ SO_3= 1\ mol$

So, according to definition of mole fraction:

$Mole\ fraction\ of\ CH_4=\frac {n_{CH_4}}{n_{CH_4}+n_{N_2}+n_{SO_3}}$

$Mole\ fraction\ of\ CH_4=\frac {4}{4+2+1}=0.57$

Learn more:-

https://brainly.in/question/4472164

https://brainly.in/question/11393456

https://brainly.in/question/2976192

#learnwithbrainly