Question

if 56x32y is divisible by 18 find the least value of y​

Answer 1

Here, I take ‘x’ to mean “multiplication” and not a missing digit.

Just look at the two numbers

56 and 32y.

If their product is to be divisible by 18, which is a multiple of 3, either of the two numbers 56 and 32y should be divisible by 9.

Since 56 is not divisible by 9, 32y should be a multiple of 9. The sum of the digits 3+2+y = 5+y. So y should be 4 for the number to be a multiple of 3.

Answer is y = 4.

Answer 2

The least value of y is 0.

Step-by-step explanation:

Since we have given that

$56x32y$ is divisible by 18.

So, it must be divisible by 9 and 2 as well.

As we know that for divisibility of 2, last digit should be even

and for divisibility of 9, sum of all digits should be divisible by 9.

Let y = 0

Then, 5+6+x+3+2+0=11+5=16+x= 16+2 = 18

So, y= 0 and x = 2

Hence, the least value of y is 0.

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56x32y is divisible by 18 then find the least value of y

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