if 56y3 is a multiple of 9 where y is a digit, what is the value of y
Answers
Step-by-step explanation:
DIVISIBILITY RULE OF 9 IS THE SUM OF DIGITS SHOULD BE DIVISIBLE BY 9
Sum = 5+6+y+3
sum = 14+y
The nearest multiple of 9 to 14 is 18
18=14+y
y = 4
the given number is 5643
The value of y = 4
Given :
56y3 is a multiple of 9 where y is a digit
To find :
The value of y
Concept :
Divisibility rule of 9 :
If the sum of the digits of a number is divisible by 9 , then the number is divisible by 9
Solution :
Step 1 of 3 :
Write down the given number
Here the given number is 56y3
Step 2 of 3 :
Find sum of the digits
The sum of the digits
= 5 + 6 + y + 3
= y + 14
Step 3 of 3 :
Find the value of y
We know that if the sum of the digits of a number is divisible by 9, then the number is divisible by 9
Since 56y3 is a multiple of 9
So 56y3 is divisible by 9
⇒ y + 14 is divisible by 9
Since y is a digit
∴ y = 4
Hence the required value of y = 4
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