Math, asked by dityawaghmode, 6 months ago

if 56y3 is a multiple of 9 where y is a digit, what is the value of y​

Answers

Answered by nikhitreddy2006
5

Step-by-step explanation:

DIVISIBILITY RULE OF 9 IS THE SUM OF DIGITS SHOULD BE DIVISIBLE BY 9

Sum = 5+6+y+3

sum = 14+y

The nearest multiple of 9 to 14 is 18

18=14+y

y = 4

the given number is 5643

Answered by pulakmath007
1

The value of y = 4

Given :

56y3 is a multiple of 9 where y is a digit

To find :

The value of y

Concept :

Divisibility rule of 9 :

If the sum of the digits of a number is divisible by 9 , then the number is divisible by 9

Solution :

Step 1 of 3 :

Write down the given number

Here the given number is 56y3

Step 2 of 3 :

Find sum of the digits

The sum of the digits

= 5 + 6 + y + 3

= y + 14

Step 3 of 3 :

Find the value of y

We know that if the sum of the digits of a number is divisible by 9, then the number is divisible by 9

Since 56y3 is a multiple of 9

So 56y3 is divisible by 9

⇒ y + 14 is divisible by 9

Since y is a digit

∴ y = 4

Hence the required value of y = 4

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