Question

if 578×4 is divisible by 3 , find the least value of x​

Answer 1

Answer:

We know, if a no is divisible by 3 then sum of all three digits is divisible by 3.

Now, 5 + 7 +8 + x + 4 = 24 +x

Now, 24 is divisible by 3 therefore x = 0 is the least value of x.

Answer 2

578×4=2312

hence 2312 is not divisible by 3 . 1 must be added to 2312 to be divisible by 3

Hope it helps

Mark the brainliest and click the thanks button

And don't forget to follow me