Question

If 58.3406 = 5A + 8/B + 3C + 4D + 6/E then find the value of 7A+6B+5C+4D+3E?​

Answer 1

$\huge \sf {\orange {\underline {\pink{\underline {♡A᭄ɴsᴡᴇʀ࿐ \ :- }}}}}$

Given, u=5a+6b+7c

v=7a−8b+9c

and w=3a+20b+5c

Now, u=lv+mw

⇒(5a+6b+7c)=l(7a−8b+9c)+m(3a+20b+5c)

⇒(5a+6b+7c)=(7l+3m)a+(20m−8l)b+(5m+9l)c

On comparing, we get

7l+3m=5     .... (i)

20m−8l=6   .... (ii)

and 5m+9l=7    .... (iii)

On multiply by 4 in Eq. (iii) and then subtracting from Eq. (ii), we get

−8l−36l=6−28

⇒−44l=−22

Therefore, l=21 then from Eq. (ii), m=21.

Answer 2

$\huge \underline \mathtt \red {αиѕωєя}$

Given, u=5a+6b+7c

v=7a−8b+9c

and w=3a+20b+5c

Now, u=lv+mw

⇒(5a+6b+7c)=l(7a−8b+9c)+m(3a+20b+5c)

⇒(5a+6b+7c)=(7l+3m)a+(20m−8l)b+(5m+9l)c

On comparing, we get

7l+3m=5     .... (i)

20m−8l=6   .... (ii)

and 5m+9l=7    .... (iii)

On multiply by 4 in Eq. (iii) and then subtracting from Eq. (ii), we get

−8l−36l=6−28

⇒−44l=−22

Therefore, l=21 then from Eq. (ii), m=21.