if 5897x is divisible by 3 ,find all the possible value of digit x
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5+8+9+7=28
28/3= the result is 9 and the remainder is 1
So, the value of x can be, 2,5 and 8.
NitinGogad:
thnx bhai
bhai 28 ki side p 29 aayega
28+2=30
so, 30 is divisible by 3
okk
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