Question

If 5a + 1/3a = 5, the value of 9a2 + 1/25a2 is​

Answer 1

Answer:

39/5

Step-by-step explanation:

Solved in the picture provided.

Answer 2

The required value is $\dfrac{119}{5}$

Step-by-step explanation:

Since we have given that

$5a+\dfrac{1}{3}a=5$

We need to find the value of

$9a^2 + \dfrac{1}{25}a^2$

So, we will multiply by $\dfrac{3}{5}$

So, it becomes,

$\dfrac{3}{5}(5a+\dfrac{1}{3a})=\dfrac{3}{5}\times 5\\\\3a+\dfrac{1}{5a}=3$

On Squaring the both sides,

$(3a+\dfrac{1a}{5})^2=5^2\\\\9a^2+\dfrac{a^2}{25}+2\times 3a\times \dfrac{a}{5}=25\\\\9a^2+\dfrac{a^2}{25}+\dfrac{6}{5}=25\\\\9a^2+\dfrac{a^2}{25}=25-\dfrac{6}{5}=\dfrac{125-6}{5}=\dfrac{119}{5}$

Hence, the required value is $\dfrac{119}{5}$

# learn more:

Evaluate (a+5) (3a-2) (5a+1)

https://brainly.in/question/11973660