Question

If 5A and 4A are acute angles satisfying sin5A = cos4A , then 2sin3A-√3tan3A = ?

Answer 1

sin 5a=cos 4a
sin 5a=sin (90-4a)
5a=90-4a
9a=90
a=10
2sin 3a -√3tan 3a
2 sin 30-√3 tan 30
2×1/2-√3×1/√3
0