Math, asked by arpan00180, 3 days ago

If 5b6 is exactly divisible by 3, then the least value of b is​

Answers

Answered by sujalchak9
0

Answer:

1 is the correct answer

Step-by-step explanation:

516/3=172

Answered by Anonymous
5

Step-by-step explanation:

 \tiny{ \boxed{ \frak{ \dag \:  \green{Your} \:  \: \blue{Required} \:  \:  \green{Answer}}}}

To Find the value of b we first have to know about the divisibility test of 3

If we want to find whether the number is divisible by 3, we have to add the numbers and if it the number after the addition of the number is exactly divisible by 3 then the number is divisible by 3. As-

We take 2 examples-

First, tell the number 729 is divisible by 3 or not

So, sum of digits = 7 + 2 + 9 = 18

Hence, 18 is exactly divisible by 3 (18 ÷ 3 = 6)

So, the number 729 is divisible by 3

Another 217

So,

Sum of digits = 2+1+7 =10

Hence, 10 is not exactly divisible by 3 (10÷3=3.333...)

Hence, 217 is not divisible by 3

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Now come to the question,

5b6

Sum of digits = 5+b+6 = 11+b

Now the nearest number to 11+b which is exactly divisible is 3 is 12. So,

☞11+b = 12

☞b = 12-11 = 1

So, Required number = 516

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Verification.

Sum of digits = 5+1+6 = 12

Hence 12 is divided by 3 (12÷3=4)

So, the least value of b = 1

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