If 5C of charge flows through a conductor in 2seconds, then the number of electrons flowing in 2s,
then the number of electrons flowing through a conductor in one second is
(a) 30×10^18
(b) 15.6×10^18
(c) 6×10^18
(d) 12×10^18
Answers
Answered by
2
Answer:
answer is b
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Answered by
2
Answer:
b) 15.6 × 10^18 electrons per second
Explanation:
We know that, Q = ne
Here, I = Q/ T
I = 5
Therefore,
I = ne/t
5 = n × 1.6 × 10 ^ -19 × 2
n = 5/3.2 × 10^ -19
n = 1.56 × 10 ^ 19
n = 15.6 × 10^18 electrons per second
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