if 5cosA = 12 sunA , prove that tan^2A-sun^2A= sin^4A.sec^2A
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Answer:
given
5cosA =12sinA __________________[1
we have to prove
tan^2-sin^A=sec^4A×sin^4A ________[2
from eqn (1)
sinA/cosA = 5/12= tanA
and sinA=[5/12](cosA)
put value of tanA and sinA in eqn(2)
L.H.S= tan^2A-sin^2A
= (25/144)-[25/144](cos^2A)
= (25/144)(1-cos^2A)= (25/144)sin^2A
R.H.S = sin^4A×sec^4A =[(5/12)^4*[cos^4A]×
Step-by-step explanation:
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