if (5cosX+ 12sinX = 13) then prove that tanX=12
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(5sinx+12siny)
2
+(5cosx+12cosy)
2
=169+120cos(x−y)
(5sinx+12siny)
2
+169=169+120cos(x−y)
(5sinx+12siny)
2
=120cos(x−y)
(5sinx+12siny)=
120cos(x−y)
This is maximum when cos(x−y) is maximum, which is 1 or (x=y)
5cosx+12cosx=13
cosx=
17
13
which is possible.
Hence,
5sinx+12siny=
120
is the maximum value
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