Question

if 5cot A = 6 find the value of 3sin A - cos A / 5cos A + 9sin A ​

Answer 1

Answer:

Step-by-step explanation:

5cot A = 6

Cot A=6/5=b/p

By pythagoras theorem,

h²=p²+b²

h²=5²+6²=61

h=√61

Now,

sin A=p/h =5/√61

cos A =b/h=6/√61

3sin A - cos A= 3×5/√61-6/√61 =1.15

5cos A + 9sin A ​=5×6/√61+9×5/√61 =9.60

Now,

3sin A - cos A / 5cos A + 9sin A ​=1.15/9.60 =0.1197