If 5cotA=12 then find sin^A+cos^A
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Answered by
0
Step-by-step explanation:
Solution :
(sin A+ cos A)x cosec A
=SinACosecA+cosAxCosecA
=1+CosA/SinA
=1+CotA
=1+12/5
=5+12/5
=17/5
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Answered by
2
5cotA =12
cotA = 12/5 means b =12 , p=5
H^2=12^2+5^2
H =√144+25=√169
H = 13
sinA + cosA
p/h +b/h
5/13+12/13
5+12/13
17/13
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