Question

If 5is the zero of the polynomials f(x) =ax2+(2a+1) x_5than value of ais

Answer 1

Given :

The zero of the polynomial is = 5

Polynomial = f(x) = ax²+(2a+1)

To Find :

The value of a.

Solution :

Put x = 5

ax²+(2a+1)

a(5)²+(2a+1)

= a(25)+2×a+1

=25a+2a+1

=27a+1

Consider 27a+1 = 0

27a=-1

a = -1/27

$a = - \frac{1}{27}$

Answer 2

Putting x = 5 and considering the polynomial equal to 0 .

ax²+(2a+1) = 0

a(5)²+(2a+1) = 0

a(25)+2×a+1 = 0

25a+2a+1 = 0

27a+1 = 0

27a=-1

a = -1/27

$a = - \frac{1}{27}$

THANK YOU !!