If 5KJ of work is done in lifting 20kg of water to the top of a building , calculate the height of the building ( take g = 10 m /s)
Answers
Answered by
4
While lifting the height increases, so potential energy exists and kinetic energy become zero
Work = 5KJ = 5000 J, m= 20
Work done = 1/2 mv² + mgh
5000 = 0 + 20×10×h
5000/200 = h
25= h
Height = 25m
Therefore height of the building is 25m
Answered by
1
Answer is in attachment
Attachments:
Similar questions