If 5L of SO2 is burnt in excess air to form SO3, what would be the volume of SO 3 formed?
Answers
Answer:
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Concept:
Fuel and an oxidant react to create oxidized products during combustion. In most cases, energy is required to start the reaction. Once combustion begins, the heat that is emitted may support it on its own.
Given:
The volume of SO₂ = 5 L
Find:
If 5 L of SO₂ is burnt in excess air to form SO₃, what would be the volume of SO₃ formed?
Solution:
The complete balanced chemical reaction of SO₂ to SO₃ is as follows below.
2SO₂ + 3O₂ → 2SO₃
From this chemical equation, we came to know that 2 moles of sulfur dioxide completely burn into 2 moles of sulfur trioxide.
So, 5 liters of sulfur dioxide are burnt in excess air to form 5 liters of sulfur trioxide.
Hence, if 5 L of SO₂ is burnt in excess air to form SO₃, then the volume of SO₃ formed is 5 L.
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