Question

if 5m/s and 10m/s are the two velocities of a body having a uniform acceleration in same time interval . what will be its average velocity

Answer 1

We know average vel.=total dist/total time
Let distance be x
So, for first vel, time taken=x/5
and for second vel, time taken=x/10
now average vel=x+x/(x/5+x/10)
=2x/(2x+x/10)
=2x/3x/10
=2x*10/3x
=20/3m/s
=6.66?/s

Answer 2

Answer:

We know average velcity=total distance/total time

Let distance be x

So, for first velocity, time taken=x/5

and for the second velocity, time taken=x/10

now average velocity=x+x/(x/5+x/10)

=2x/(2x+x/10)

=2x/3x/10

=2x*10/3x

=20/3m/s

=6.66m/s

Hope this helps........

:)