Question

if 5secΦ=13 ,find the value of
2sinΦ+3tanΦ
4sinΦ - 9cos Φ​

Answer 1

Step-by-step explanation:

5secΦ= 13

secΦ= 13/5

h/b= 13/5

hence b = 5 and h= 13

p²=h²-b²

p²= 13²-5²

p²= 169-25

p²= 144

p= 12

2sinΦ+3tanΦ

2×p/h+3p/b

2× 12/13 + 3×12/5

24/13+36/5

588/65

. 4sinΦ - 9cos Φ

4p/h -9b/h

4×12/13 - 9×5/13

48/13-45/13

3/13

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