Question

If 5sec theta - 12 cos theta =0, find the values of sec theta,cos theta,sin theta​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$5sec \alpha = 12cos \alpha$

$\frac{5}{cos \alpha } = 12cos \alpha$

${cos}^{2} \alpha = \frac{5}{12}$

$cos \alpha = \sqrt{ \frac{5}{12} } = \frac{ \sqrt{5} }{2 \sqrt{3} }$

$sec \alpha = { \frac{2 \sqrt{3} }{ \sqrt{5} } }$

$sin \alpha = \sqrt{1 - {cos}^{2} \alpha } = \sqrt{1 - \frac{5}{12} } = \sqrt{ \frac{7}{12} } = \frac{ \sqrt{7} }{2 \sqrt{3} }$