if 5sec theta=13 then prove that sin theta=12by13
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Answered by
8
since
5sec@=13,
then
sec@=13/5,
then
cos@=5/13,
now
sin²@=1-cos²@,
sin²@=1-(5/13)²,
sin²@=1-25/169,
sin²@=(169-25)/169,
sin²@=144/169,
then
sin@=√(144/169),
sin@=12/13
5sec@=13,
then
sec@=13/5,
then
cos@=5/13,
now
sin²@=1-cos²@,
sin²@=1-(5/13)²,
sin²@=1-25/169,
sin²@=(169-25)/169,
sin²@=144/169,
then
sin@=√(144/169),
sin@=12/13
Answered by
5
please see this answer.
hope it helps.
hope it helps.
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