Question

If 5sec thita - 12cosec thita =0, find the value of sin thita and cos thita​

Answer 1

Step-by-step explanation:

Hey !!

Cosec ¢ = Hypotenuse / Perpendicular

And,

Sec ¢ = Hypotenuse / Base

Given :- 5 Sec ¢ - 12 Cosec ¢ = 0

5 Sec ¢ = 12 Cosec ¢

Cosec ¢ / Sec ¢ = 5/12

Hypotenuse / Perpendicular / Hypotenuse / Base = 5/12

Hypotenuse / Perpendicular × Base / Hypotenuse = 5/12

Base / Perpendicular = 5/12

Base = 5 and Perpendicular = 12

By Pythagoras theroem ,

( Hypotenuse )² = ( Base )² + ( Perpendicular)²

( Hypotenuse )² = (5)² + (12)²

( Hypotenuse )² = 169

Hypotenuse = √169

Hypotenuse = 13

Therefore,

Sec ¢ = Hypotenuse / Base = 13/5

Cos ¢ = Base / Hypotenuse = 5/13

Sin ¢ = Perpendicular/ Hypotenuse = 12/13

Answer 2

Answer:

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