if 5sin A = 3 find sec A - cosec A
Answers
Answer:
we have ......
5 sin A = 3
then .. sin A = 3/5
WKT.......
sin *2 (A). + cos *2 (A ) = 1
( 3/5 ) *2 + cos*2 (A) = 1
cos*2 (A) = 1 - 9/25
cos*2 (A) = 25 - 9 /25
cos*2 ( A) = 16/15
cos (A) = 4/5
then .... we find ..
sec A = 5/4
cosec A = 5/3
then.....
sec A - cosec A
5/4 - 5/3
15/12 - 20/12
-5/12 ....
hence sec A - cosec A = -5/12 .....
..... Hope you are understand .......
Answer:
secA - cosecA = -5/12
Step-by-step explanation:
Given that, sinA = 3/5
WKT,
cos²A= 1 - sin²A
=1 - (3/5)²
= 1 - 9/25
=(25 - 9)/25
=16/25
cos²A = 16/25
cosA = 4/5
secA - cosecA = 1/cosA - 1/sinA
=1/4/5 - 1/3/5
= 5/4 - 5/3
=(15 - 20)/12
= -5/12