If 5sin theata =3 then cos theata
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Answer: sinQ=3/5=p/h
By using Pythagoras theorem:
B=4
CosQ=b/h
CosQ=4/5
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▶ Question :-
→ If 5 sin theta(∅) = 3, then cos theta (∅) .
▶Answer :-
→ cos ∅ = 4/5 .
▶ Step-by-step explanation :-
➡ Given :-
→ 5 sin ∅ = 3 .
°•° sin ∅ = 3/5 .
➡ To find :-
→ cos ∅ .
We have,
°•° sin ∅ = 3/5 = p/h .
[ •°• p = 3 , h = 5 . ]
We know that,
→ h² = p² + b² .
==> b² = 5² - 3² .
==> b² = 25 - 9 .
==> b = √(16) .
•°• b = 4 .
▶ Therefore, cos ∅ = b/h .
✔✔ Hence, it is solved ✅✅.
THANKS
→ If 5 sin theta(∅) = 3, then cos theta (∅) .
▶Answer :-
→ cos ∅ = 4/5 .
▶ Step-by-step explanation :-
➡ Given :-
→ 5 sin ∅ = 3 .
°•° sin ∅ = 3/5 .
➡ To find :-
→ cos ∅ .
We have,
°•° sin ∅ = 3/5 = p/h .
[ •°• p = 3 , h = 5 . ]
We know that,
→ h² = p² + b² .
==> b² = 5² - 3² .
==> b² = 25 - 9 .
==> b = √(16) .
•°• b = 4 .
▶ Therefore, cos ∅ = b/h .
✔✔ Hence, it is solved ✅✅.
THANKS
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