if 5sin theeta =12 cos theeta then tan thete=?
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5 sin theeta =12cos theera
Sin theeta/cos theeta= 12/5
Tan theera =12/5
Sin theeta/cos theeta= 12/5
Tan theera =12/5
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Let theta be A
5 sin A = 12 cos A
sin A / cos A = 12 /5
tan A = 12 / 5
5 sin A = 12 cos A
sin A / cos A = 12 /5
tan A = 12 / 5
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