Question

if 5sinA=3,find the value of cos *A+sin*A​

Answer 1

Answer:

1

sinA=p/h=3/5

p=3

h=5

b=?

by pythagoras theorem

h*=p*+b* (*=2 or square)

5*=3*+b*

25=9+b*

b*=25-9

b*=16

b=4

sin*A+cos*A = (p/h)* + (b/h)*

= (3/5)*+(4/5)*

= 9/25+16/25

=25/25 = 1

Answer 2

_____Hello..Buddy✌️✌️____

_We have _:

5sinA = 3

sinA = 3/5

sinA = 3/5 =

(perpendicular) / (Hypotenuse)

-> So,,by Pythagoras Theorem;_

(Base)^2 =

(Hypotenuse)^2 - (Perpendicular)^2

= (5)^2 - (3)^2

= 25 - 9

= 16

Base = √16

Base = 4

->Hence,,__

cosA = (Base) / (Hypotenuse)

= 4/5

➡️Now , we have to find the value of ;

cosA + sinA = ( 4/5 ) + (3/5)

= 7/5. ⬅️

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