Question

If 5sinA = 3, find the value of sec2 A + tan2 A.
I am having online class please help me

Answer 1

given 5sinA=3

sinA=3/5 => opposite side to A/hypotenuse =3/5,then opp side of A=3 and hyp=5 let another side take as X

by Pythagoras theorem

hyp²=side²+side²

5²= 3²+x²

25-9=x²

4=x

now you can find sec2A+tan2A easily

I am not understanding here whether it is sec²A+tan²A or sec2A+tan2A so I stopped giving full solution

hope it will help you a bit