If 5sinA – 4 = 0, find the value of 3tanA + 5cosA.
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Answer:
7
Step-by-step explanation:
5sinA-4=0
sinA=4/5 (sin=p/h)
now find base
by pythagoras theorem
h^2=p^2+b^2
25=16+b^2
b=3
now, ATQ
3tanA +5cosA
put the value of tanA and cosA
3×4/3+5×3/5
4+3
=7
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