if 5sinO-7cosO=0 then find the value of secO
Answers
Answered by
4
HEY MATE!!
The answer to your question is!!
5sinO-7cosO=0
-7cosO=-5sinO
cosO=5sinO÷7
secO=1/cosO
secO=7/5sinO
HOPE IT HELPS YOU
The answer to your question is!!
5sinO-7cosO=0
-7cosO=-5sinO
cosO=5sinO÷7
secO=1/cosO
secO=7/5sinO
HOPE IT HELPS YOU
Answered by
0
Answer:
Step-by-step explanation:
5sinO - 7cosO=0
5sinO = 7cosO
sinO/cosO = 7/5
tanO = 7/5
secO = root under(1 + tan^2O)
= root under(1 + 49/25)
= root under{(25+49)/25}
= root under 74/5 ans.
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