If 5tan∅=4, find the value of 5sin∅-3cos∅/5sin∅+2cos∅.
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Answer:
Given,
5tan$=4
tan$=⅘
P/H=⅘
Now, By Pythagoras theorem..
H² = P² + B²
H² = 4² + 5²
H² = 16 + 25
H² = 41
H = ✓41
Hence,
5sin$ - 3sin$ / 5sin$ + 2cos$
= 5×4/✓41 - 3×5/41 / 5×4/✓41 + 2 ×5/✓41
= 20 - 15 / 20 + 10
= 5/30
= 1/6
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