if 5tan alpha = 4 then find the value of 5 sin alpha - 3cos alpha\ 5sin alpha + 2cos alpha = 1/6
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5 sin θ-3 cos θ /5sinθ +2 cosθ
= cos θ [(5sin θ/cos θ) - 3] / cos θ[(5sin θ/cos θ) + 2]
(Take out cos θ as the common factor from both numerator & denominator)
= 5tan θ-3 / 5tan θ+2
Substitute 5tan θ=4 in the above equation
= ( 4-3)/(4+2) = 1/6 (Ans)
= cos θ [(5sin θ/cos θ) - 3] / cos θ[(5sin θ/cos θ) + 2]
(Take out cos θ as the common factor from both numerator & denominator)
= 5tan θ-3 / 5tan θ+2
Substitute 5tan θ=4 in the above equation
= ( 4-3)/(4+2) = 1/6 (Ans)
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