if 5tan theta = 4, write the value of (cos theta - sin theta)÷(cos theta + sin theta)
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5tan@ = 4
tan@ = 4/5
tan@ = opposite side/adjacent side
therefore ,
opposite side = 4
adjacent side = 5
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let take hypotenuse as x,
x² = 4²+5²
x² = 16+25
x² = 41
x = √41
hypotenuse = √41
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so,
cos@-sin@/cos@+sin@
= (5/√41 - 4/√41)/(5/√41 + 4/√41)
= (1/√41)/(9/√41)
= 1/√41 × √41/9
= 1/9
tan@ = 4/5
tan@ = opposite side/adjacent side
therefore ,
opposite side = 4
adjacent side = 5
___________________
let take hypotenuse as x,
x² = 4²+5²
x² = 16+25
x² = 41
x = √41
hypotenuse = √41
__________________
so,
cos@-sin@/cos@+sin@
= (5/√41 - 4/√41)/(5/√41 + 4/√41)
= (1/√41)/(9/√41)
= 1/√41 × √41/9
= 1/9
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