If 5tanA =12, find (cosecA -cotA) , (
cosecA+cotA)
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Step-by-step explanation:
5tanA=12
tanA=12/5
tanA=perpendicular/base
Therefore, perpendicular=12
base=5
By Pythagoras Theorem,
AC^2= AB^2 + BC^2
AC^2= 5^2 + 12^2
AC^2= 25 + 144
AC^2= 169
AC =√169
= 13
Therefore, hypotenuse=13
cosecA= hypotenuse/perpendicular
= 13/12
cotA= base/perpendicular
= 5/12
cosecA - cotA= 13/12 - 5/12
= 8/12
= 2/3
cosecA + cotA= 13/12 + 5/12
= 18/12
= 3/2
"Hope this helps you..."
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