Question

. if 5tanA= 3 then value of (5sinA-3cosA /4sinA+ 3cosA)?​

Answer 1

3sinA+5cosA=5

⇒(3sinA+5cosA)

2

=25

⇒9sin

2

A+25cos

2

A+30sinAcosA=25 ……(1)

Let (3cosA−5sinA)

2

=k

⇒9cos

2

A+25sin

2

A−30sinAcosA=k …….(2)

(1)+(2)

⇒9(sin

2

A+cos

2

A)+25(cos

2

A+sin

2

A)=25+k

⇒9+25=25+k

⇒k=9.

copied hai to be honest

hope it helps

Answer 2

Answer:

5tanA = 3

tanA = 3/5

TanA = p/b

h=✓p²+b² = ✓3²+5² = ✓ 9+25 = ✓34

h = ✓34

Now sinA = p/h = 3/✓34

cosA = 5/✓34

5sinA - 3cosA ÷ 4sinA + 3cosA

15/✓34 - 15/✓34 ÷ 12/✓34 + 15/✓34

0 ÷ 17/✓34

= 0

Another way

Divide 5sinA-3cosA/ 4sinA+3cosA by cos A

we will get

5tanA-3/4tanA+3

= 3-3 / 4tanA +3 (because 5tanA = 3)

= 0/ 4tanA + 3

= 0 (0 upon anything is 0)

Hope it helps you.

Mark as brainliest please