If 5tanA = 4, find the value of 5sin A -3cos A/5sin A + 2cos A
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I think it is correct process
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5tanA= 4
tanA= 4/5
then,
sinA=4/√41
cosA=5/√41
solution is
tanA= 4/5
then,
sinA=4/√41
cosA=5/√41
solution is
Attachments:
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