Question

If 5th and 11th term of an Ap are 16 and 34 find AP​

Answer 1

Answer:

t5 = 16

16 = a + 4d .............. ( 1)

t11= 34

34 = a + 10d (2)

Substracting (1) from (2)

18 = 6d

d = 3

Putting d = 3 in (1)

$16 = a + 12 \\ a = 4$

So, t1 = 4, t2= 7 , t3 =10

So, The AP is 4, 7, 10, 14, 16.....

Answer 2

Answer:

4,7,10,13,16,.......

Step-by-step explanation: