Question

if 5th and 12th terms of an A.P are 14 and 35 respectively find the
A.p

Answer 1

hello friend !! here is your answer....

hope it helped☺☺

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Answer 2

Answers:

$\huge{\red{\boxed{\boxed{\green{\sf{a=2\:and\:d=3\:so,A.P=2,5,8,11,14,.......}}}}}}$

Step-by-step explanation:

$\huge{\red{\boxed{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}}$

□a5=14

□a12=35

To find:

☆A.P=?

$a5 = 14 \\ a + 4d = 14 - - - - - - (1) \\ \\ a12 = 35 \\ a + 11d = 35 - - - - - (2) \\ \\ subtracting \: (1) \: from \: (2) \\ = )a + 11d - (a + 4d) = 35 - 14 \\ = ) a + 11d - a - 4d = 21 \\ = )7d = 21 \\ = )d = \frac{21}{7} \\ = )d = 3 \\ \\ putting \: value \: of \: d \: in \: (1) \\ = )a + 4d = 14 \\ = )a + 4 \times 3 = 14 \\ = )a + 12 = 14 \\ = )a = 14 - 12 \\ = )a = 2$

$\huge{\red{\boxed{\boxed{\green{\sf{a=2\:and\:d=3\:so,A.P=2,5,8,11,14,.......}}}}}}$

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