Question

If 5th and 6th term of an A.P. are respectively 6 and 5 find the 11th term of the A.P.

Answer 1

Answer:

Step-by-step explanation:

T5 =a+(n-1) d = 6

=a + 4d =6 ....... (1)

T6 = a+(n-1) d = 5

=a+5 d = 5 ..... (2)

From 1 and 2 we get

=a+5 d = 5

=a + 4d =6

=d = -1

On substituting the value of d in eq 1

=a + 4d =6

=a + 4(-1) =6

=a =6 +4

a = 10

Therefore

T11 = =a+(n-1) d

= 10 + 10(-1)

= 10 -10

= 0