Question

If 5th term of a G.P is 32 and its 7th term is 128. Find geometric sequence​

Answer 1

Step-by-step explanation:

5th term is (a r^4) = 32 (1)

7th term is ( a r^6) = 128

${r}^{6} = {r}^{2 + 4} = {r}^{2} . {r}^{4}$

(ar⁴)r²= 128

32 r²= 128

r²=4

r=2 (put this in eqn 1)

a.16=32

a=2

GP : 2,4,8,16...