If 5th term of a GP is 3√3 then product of 1st 9 terms is
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Given: 5th term of a Geometric Progression is 3√3
To find: The product of 1st 9 terms?
Solution:
- Now we have given 5th term as 3√3.
ar^4 = 3√3
- Now the series of Geometric Progression is:
= a x ar x ar^2 x ar^3 x ar^4 x ar^5 x ar^6 x ar^7 x ar^8
= a^9r^36
- Now (ar^4)^9 = a^9r^36
- So putting the value in this, we get:
= (3√3)^9 = a^9r^36
= a^9r^36 = 19683 x 81√3
= a^9r^36 = 1594323√3
Answer:
The product of 1st 9 terms is 1594323√3.
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