If 5th term of an A.P. is 14 and 11th term is 26, then its 21st term is:
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let 1st term is a and common difference is d
a+(5-1).d=14
=> a+4d=14
=> a=14-4d
a+(11-1).d=26
=> a+10d=26
=> 14-4d+10d=26
=> 6d=26-14
=> 6d=12
=> d=12/6
=> d=2
then a=14-4d=14-4×2=14-8=6
21 th term=a+(21-1).d=6+20×2=6+40=46
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