Question

If 5th term of an A.P. is zero, then show that its
33rd term is four times its 12th term.
Fill in the Blanks​

Answer 1

Given

The 5th term of the AP is 0

$\implies a+4d = 0\\ \implies a = -4d --(1)$

To show

33rd term is four times the 12th term

LHS

$= a + 32d$

$= -4d+32d$

(From equation 1

$= 28d$

RHS

$=a+11d$

$= -4d+11d$

$= 7d$

$\boxed{\boxed{\bold{Therefore, \ the \ 33rd \ term \ is \ 4 \ times \ the \ 12th \ term}}}}}$

                                                     

Answer 2

$\rule{200}2$

$\huge\tt{PROBLEM:}$

• If 5th term of an A.P. is zero, then show that its 33rd term is four times its 12th term.

$\rule{200}2$

$\huge\tt{SOLUTION:}$

↪a + 32d = a + 11d

↪-4d + 32d = -4d + 11d

↪28d = 7d

Therefore, It's 33rd term is four times it's 12th term.

$\rule{200}2$