If 5th term of an ap is 1/9 and 9th term is 1/5. Find the common difference,first term and sum of 45th term
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Step-by-step explanation:
a5 = 1/9
or, a + 4d = 1/9
or, a = 1/9 - 4d _____(i)
a9 = 1/5
or, a + 8d = 1/5
or, a = 1/5 - 8d _____(ii)
Equating equations (i) and (ii), we get,
1/9 - 4d = 1/5 - 8d
-4d + 8d = 1/5 - 1/9
4d = (9-5)/45
4d = 4/45
d = 1/45
∴ Common Difference = 1/45
Then, Putting the value of d in eqn (i),
a = 1/9 - 4/45
= (5-4)/45
= 1/45
∴ a45 = a + 44d
= 1/45 + 44/45
= (1 + 44)/45
= 45/45
= 1
∴ 45th term of this AP = 1
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