if 5th term of an ap is zero then show that its 33rd term is two times its 19th term
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Step-by-step explanation:
5th term = a+ 4d =0 so a= -4d
Now 19th term = a+18d = -4d +18d =14d from. (I)
Now 33term = a + 32d = -4d+32d = 28d
So 28d =2(14d)
Hence it is proved that 33 term is twice of 19th term
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