If 5th term of an arithmetic sequence is 20 ,find sum of first 9 terms
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hey here is your solution
pls mark it as brainliest pls
so here we go
Step-by-step explanation:
now here t5=20
this apply formula
tn=a+(n-1)d
put n=5
so t5=a+(5-1)d
ie a+4d=20 (1)
so now to find sum of first 9 terms
apply fornula
Sn=n/2(2a+(n-1)d)
put n=9
so S9=9/2×(2a+(9-1)d)
=9/2×(2a+8d)
=9/2×2(a+4d)
=9/2×(2×20) from (1)
=9/2×40
=9×20
so S9=180
thus sum of its first 9 terms is 180
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