Question

if 5th term of AP is zero show that 33 rd yerm is two times its 19th term

Answer 1

Solution for your question

Answer 2

Answer:

33th term is two times its 19th term.

Step-by-step explanation:

The nth term of an AP is

$a_n=a+(n-1)d$

It is given that if 5th term of AP is zero.

$0=a+(5-1)d$

$0=a+4d$

$a=-4d$

We have to proof that 33th term is two times its 19th term.

33th term of AP is

$a_{33}=a+(33-1)d=-4d+32d=28d$

19th term of AP is

$a_{19}=a+(19-1)d=-4d+18d=14d$

$28d=2\times 14d$

$a_{33}=2\times a_{19}$

Hence proved that 33th term is two times its 19th term.